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* from \"-!../../../node_modules/mini-css-extract-plugin/dist/loader.js??ref--8-oneOf-1-0!../../../node_modules/css-loader/index.js??ref--8-oneOf-1-1!../../../node_modules/vue-loader/lib/loaders/stylePostLoader.js!../../../node_modules/postcss-loader/src/index.js??ref--8-oneOf-1-2!../../../node_modules/sass-loader/dist/cjs.js??ref--8-oneOf-1-3!../../../node_modules/cache-loader/dist/cjs.js??ref--0-0!../../../node_modules/vue-loader/lib/index.js??vue-loader-options!./SubTopics.vue?vue&type=style&index=0&id=b3a0d23c&prod&scoped=true&lang=scss&\"","var render = function render(){var _vm=this,_c=_vm._self._c;return _c('div',{staticClass:\"font-weight-light\",class:{'pa-5 headline': _vm.$vuetify.breakpoint.lgAndUp,'pa-2 subtitle-1': _vm.$vuetify.breakpoint.mdOnly, 'pa-1 body-2': _vm.$vuetify.breakpoint.smAndDown}},[_c('div',{staticClass:\"font-weight-medium\",class:{'display-1': _vm.$vuetify.breakpoint.lgAndUp,'headline': _vm.$vuetify.breakpoint.mdOnly, 'subheading': _vm.$vuetify.breakpoint.smAndDown}},[_c('span',{staticStyle:{\"font-family\":\"Roboto\"}},[_vm._v(\" Introduction\")])]),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_c('span',{staticClass:\"subhead\"},[_vm._v(\"A\")]),_vm._v(\" chemical equation is a way of representing a chemical reaction using symbols (to represent chemical entities) and numeric coefficients (to represent stoichiometry) of the various chemical entities involved in the reaction.\\n \"),_c('div',{staticStyle:{\"margin-top\":\"20px\"}}),_c('div',{staticClass:\"font-weight-medium\",class:{'display-1': _vm.$vuetify.breakpoint.lgAndUp,'headline': _vm.$vuetify.breakpoint.mdOnly, 'subheading': _vm.$vuetify.breakpoint.smAndDown}},[_c('span',{staticStyle:{\"font-family\":\"Roboto\"}},[_vm._v(\" Reactants & Products\")])]),_c('div',{ref:\"ia\",staticStyle:{\"margin-top\":\"10px\"}}),_vm._m(0),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n For example, the chemical equation representing synthesis of ammonia is given as: $$ N_2 + 3H_2 \\\\rightarrow 2NH_3$$\\n In this reaction, \\\\(N_2\\\\)(Nitrogen) and \\\\(H_2\\\\) (Hydrogen) are the reactants, and \\\\(NH_3\\\\) (Ammonia) is the product. During the reaction, 1 molecule of \\\\(N_2\\\\) reacts with 3 molecules of \\\\(H_2\\\\) to produce 2 molecules of \\\\(NH_3\\\\).\\n \"),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n It is a common practice to use the smallest whole numbers as coefficients in a chemical equation — as shown in this example.\\n \"),_c('div',{staticStyle:{\"margin-top\":\"20px\"}}),_c('v-layout',{attrs:{\"align-center\":\"\",\"justify-center\":\"\",\"row\":\"\",\"wrap\":\"\"}},[_c('v-flex',{staticClass:\"font-weight-light\",class:{'headline': _vm.$vuetify.breakpoint.lgAndUp,'body-2': _vm.$vuetify.breakpoint.mdOnly, 'body-2': _vm.$vuetify.breakpoint.smAndDown},attrs:{\"xs12\":\"\",\"sm8\":\"\",\"md8\":\"\",\"lg8\":\"\",\"xl8\":\"\"}},[_c('div',{staticClass:\"font-weight-medium\",class:{'display-1': _vm.$vuetify.breakpoint.lgAndUp,'headline': _vm.$vuetify.breakpoint.mdOnly, 'subheading': _vm.$vuetify.breakpoint.smAndDown}},[_c('span',{staticStyle:{\"font-family\":\"Roboto\"}},[_vm._v(\" Balancing a Chemical Equation\")])]),_c('div',{ref:\"ib\",staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n In a chemical reaction, matter is neither created nor destroyed, therefore every chemical reaction should be consistent with the law of conservation of mass.\"),_c('br'),_c('br'),_vm._v(\"\\n This requires that the mass of every chemical species involved in the reaction should remain the same before and after the reaction. When a chemical equation satisfies this condition, the equation is said to be \\\"balanced,\\\" otherwise, the equation is said to be \\\"unbalanced.\\\"\\n \"),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n Let's take the example of the reaction describing the synthesis of water molecules from a combination of hydrogen and oxygen molecules.\\n $$ H_2 + O_2 \\\\rightarrow H_2 O$$ Let's check if this equation is balanced or unbalanced.\\n \"),_c('br'),_vm._v(\" On the reactant side (shown on the left) — we have 2 Hydrogen atoms and 2 Oxygen atoms.\\n \"),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n On the product side (shown on the right) — we have 2 Hydrogen atoms, however, only 1 Oxygen atom.\\n \"),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n So, clearly the equation is unbalanced.\\n \"),_c('div',{staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n Let's multiply the right side by a factor of 2 so that we now have 2 Oxygen atoms on each side. $$ H_2 + O_2 \\\\rightarrow 2 H_2 O$$\\n However, now we have 4 Hydrogen atoms on the product side and only 2 of those in the reactant side. So, in order to balance the number of Hydrogen atoms, we multiply \\\\(H_2 \\\\) on the reactant side with 2, and that makes the equation balanced.\\n $$ 2 H_2 + O_2 \\\\rightarrow 2 H_2 O$$.\\n \")]),_c('v-flex',{attrs:{\"xs12\":\"\",\"sm4\":\"\",\"md4\":\"\",\"lg4\":\"\",\"xl4\":\"\"}},[_c('v-img',{staticClass:\"mx-auto px-2\",attrs:{\"padding\":\"10px\",\"max-height\":\"600px\",\"max-width\":\"600px\",\"src\":\"/assets/Dalton.jpg\",\"contain\":\"\"}}),_c('br'),_c('h5',{staticStyle:{\"text-align\":\"start\"}},[_vm._v(\"\\n Lavoisier discovered the law of conservation of mass, which states that the mass remains conserved during a chemical reaction. This principle forms the basis for balancing chemical equations.\\n \")])],1)],1),_c('div',{staticStyle:{\"margin-top\":\"20px\"}}),_c('div',{staticClass:\"font-weight-medium\",class:{'display-1': _vm.$vuetify.breakpoint.lgAndUp,'headline': _vm.$vuetify.breakpoint.mdOnly, 'subheading': _vm.$vuetify.breakpoint.smAndDown}},[_c('span',{staticStyle:{\"font-family\":\"Roboto\"}},[_vm._v(\" Lesson Plan \")])]),_c('div',{ref:\"ic\",staticStyle:{\"margin-top\":\"10px\"}}),_vm._v(\"\\n This chapter on balancing chemical equations contains three interactive lessons. 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