\n Gravitational force is an attractive force that acts between two bodies due to the virtue of their mass. Newton's law gives the magnitude of gravitational force\r\n acting between two bodies.\r\n $$F_{G} = \\frac{G m_1 m_2}{r^2}$$\r\n where \\(m_1\\) and \\(m_2\\) are the masses of the two bodies, and \\(r\\) is the distance between them (measured between their centers of mass).\r\n \\(G\\) is a universal constant called gravitation constant.\r\n
\r\n\r\n The most commonly experienced form of gravitational force is the Earth's gravity. Earth's gravity causes the objects to fall when left free.\r\n For example, when you kick a ball from the top of a building, the ball falls to the ground due to the Earth's gravity.\r\n Earth's gravity is characterized by the acceleration that an object experiences while falling under the Earth's gravity.\r\n This acceleration is called acceleration due to gravity and is commonly denoted by the symbol \\(g\\).
\r\n\r\n Let's consider an object of mass \\(m\\) that is falling from a height towards the surface of the Earth.\r\n The gravitational force experienced by this object as it falls towards Earth is\r\n $$F_G = \\frac{G m M}{R^2} = m \\frac{G M}{R^2} $$\r\n where \\(M\\) is the Earth's mass, and \\(R\\) is Earth's radius. Comparing with Newton's second law \\(F = m a\\), we\r\n obtain the acceleration due to gravity as\r\n $$a = \\frac{G M}{R^2} = g$$\r\n
\n We will examine the motion of a ball kicked from the top of a building of height \\(h\\).\r\n Let's say the kicker kicks the ball horizontally at an initial speed of \\(v\\). Thus, the initial velocity of the ball is given as\r\n $$u_x(t=0) = v$$\r\n and\r\n $$u_y(t=0) = 0$$\r\n
Through this MagicGraph, students will learn the motion of an object falling under the effect of Earth's gravity.
\r\n